t=-16t^2+20t+360

Solution for t=-16t^2+20t+360 equation:

t=-16t^2+20t+360

We move all terms to the left:

t-(-16t^2+20t+360)=0

We get rid of parentheses

16t^2-20t+t-360=0

We add all the numbers together, and all the variables

16t^2-19t-360=0

a = 16; b = -19; c = -360;
Δ = b2-4ac
Δ = -192-4·16·(-360)
Δ = 23401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{23401}}{2*16}=\frac{19-\sqrt{23401}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{23401}}{2*16}=\frac{19+\sqrt{23401}}{32}
$